IPL: Mumbai Indians beat Kings XI Punjab by three wickets
Mumbai, Apr 10 (IBNS): Mumbai Indians beat Kings XI Punjab by three wickets in the 24th match of IPL 2019 here this evening.
Batting first, Kings XI Punjab put up a formidable total of 197 losing four wickets.
K.L. Rahul scored an unbeaten 100 and Chris Gayle, 63 off 36 balls.
Mumbai Indians scored the winning runs on the very last ball.
Captain K.C.Pollard was the highest scorer of the side smashing 83 of 31 balls.
Image Credit: @IPL on Twitter
Support Our Journalism
We cannot do without you.. your contribution supports unbiased journalism
IBNS is not driven by any ism- not wokeism, not racism, not skewed secularism, not hyper right-wing or left liberal ideals, nor by any hardline religious beliefs or hyper nationalism. We want to serve you good old objective news, as they are. We do not judge or preach. We let people decide for themselves. We only try to present factual and well-sourced news.
Support objective journalism for a small contribution.
