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First ODI: South Africa win toss, elect to bat first against India Paarl ODI
Image Credit: Facebook/Indian Cricket Team

First ODI: South Africa win toss, elect to bat first against India

India Blooms News Service | @indiablooms | 19 Jan 2022, 01:51 pm

Paarl/IBNS: South African captain Temba Bavuma won the toss and elected to bat first against India in the first One Day International (ODI) here on Wednesday.

South Africa are playing with two spinners, Bavuma said at the toss.

India's stand-in captain KL Rahul, who would have loved to bat first as well, said Venkatesh Iyer is making debut in the match.

Shreyas Iyer will be batting at number four, the skipper added.

The three-match ODI series has gained traction as Kohli, who was controversially stripped off his ODI captaincy late last year, will play under someone else, this time Rahul in absence of injured regular limited overs captain Rohit Sharma, after years.

The three-match ODI series has gained traction as Kohli, who was controversially stripped off his ODI captaincy late last year, will play under someone else, this time Rahul in absence of injured regular limited overs captain Rohit Sharma, after years.

South Africa XI: Quinton de Kock (w), Janneman Malan, Aiden Markram, Rassie van der Dussen, Temba Bavuma (c), David Miller, Andile Phehlukwayo, Marco Jansen, Keshav Maharaj, Tabraiz Shamsi, Lungi Ngidi.

India XI: S Dhawan, K L Rahul (c), V Kohli, S Iyer, R Pant (wk), V Iyer, R Ashwin, S Thakur, B Kumar, J Bumrah, Y Chahal.